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Thread: Pre-Calc Help
January 29th, 2006, 12:38 PM #1
Well i need to do this online assesment of pre-calc question, there were about 60 questions total, and the only ones i have left are the following three. I hoping someone here can point me in the right direction because im not really sure how to do them.
Algebraic Properties of the Logarithm - Simplifying Formulas
4) Simplify ln(z^4 + z^2).
4 ln(z) + 2 ln(z) but it says this answer is incorrect
Algebraic Properties of the Logarithm - simplifying numbers
1) Simplify ln (3000).
12) Solve the following equation in x: 2 e^(x) = e^(4x - 2)
e^(x)^(2) = e^(4x-2) and then multiply each side by ln(x) to get
x^2 = 4x - 2 ------> x^2 - 4x - 2 but this doesnt appear to be the right answer so i know i went wrong somewhere.
Any help would be greatly appreciated : )
January 29th, 2006, 07:48 PM #2
someone has to know more math then i do! where are you math people?
January 29th, 2006, 09:26 PM #3
- Join Date
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sorry. i know up to math b....
January 29th, 2006, 09:46 PM #4
I'm in Pre-Calc now, but we did natural logs last year and I'll be damned if I remember them
And actually, number 4 seems right to me...23. That's the number of people Mr. T has pitied in the time it has taken you to read this sentence.
January 30th, 2006, 12:39 AM #5
ln(a+b) does not equal ln(a) + ln(b) !!!
you must be thinking of ln(ab) = ln(a) + ln(b)
OK I'll take a stab....
Simplify ln(z^4 + z^2)
split into separate ln terms : 2*ln (z) + ln (z^2+1)
you can reduce further, but you need to use the imaginary number "i": 2*ln (z) + ln((z+i)(z-i))
and again separate terms : 2*ln (z) + ln(z+i) + ln(z-i)
Simplify ln (3000)
factor 3000 : ln (3*10^3)
more factoring: ln (3 * 5^3 * 2^3)
split into separate ln terms : ln(3) + 3*ln(5) + 3*ln(2)
not really sure if that's what you wanted though....
2 e^(x) = e^(4x - 2)
now take the ln of both sides: x^2 = 4x-2
rewrite into quadratic equation form: 0=x^2-4x+2
this polynomial is not easy to factor so you have to use the quadratic formula:
if 0 = ax^2 + bx + c) then
x = [-b +- sqrt(b^2 - 4ac)] / [2a]
pluggin in a, b, and c you get
x=[4 +- sqrt(16-4(1)2)]/[2(1)]
x=[4 +- sqrt(8)]/2
x=[4 +- 2sqrt(2)]/2
x1= 2 + sqrt(2)
x2= 2 - sqrt(2)
hopefully I didn't screw up somewhere...
Last edited by DanU; January 30th, 2006 at 12:44 AM.
January 30th, 2006, 01:56 AM #6
Thank you so much! i am ever in your debt lol
Everything worked out perfect except for the last solution, but after doing it out i got the same exact answer as you so im not really sure whats going on with that problem. But only missing one problem out of all them isnt bad at all. So thanks again, you rock
January 30th, 2006, 05:20 AM #7
No problemo. Hope you get an "A"
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