Running commands in loop??

[brucewayne]

Hi All,

I want to execute a set of commands in unix in sequence.

say,

sh ABC.sh job1 20010505 C/..../log
sh ABC.sh job1 20010506 C/..../log
sh ABC.sh job1 20010507 C/..../log
sh ABC.sh job1 20010508 C/..../log

..

How i can write a loop to execute these commands one after another in sequence.

Also, untill the first command is runs completely, the second should not get executed.

The only variant in all these commands is the date.

I am just learning unix scripts...if someone could pitch in with their suggestions it would be great..!!


Regards,

Bruce

[SeanC]

I'm not a Unix scripting expert but I'll give it a shot.

So do you want to run them in a loop one at a time repeatedly? Or just run them one at a time once per execution of the script?

If you just want to run them once per execution, just type them into the script file, one per line. Don't forget any script headers that are needed. I think they will run one at a time, waiting for the previous one to finish before starting the next.

If you want to have them run repeatedly, you'll need to use some type of FOR loop in the scripting.

[trueg]

while [ 1 ]; do
command1
command2
....
done

[pbharris]

for i in `ls 20010*`;do sh ABC.sh job1 $i C/..../log;done

those are tick marks - not quote marks.