PHP functions

[Weeble]

Ok, in my mind this should work but it returns an error (displayed bottom) for some unknown reason, anyone have any comments?

<?php
$yes = $_POST['yes']; $no = $_POST['no'];

$yesnum = "yes.txt";
$nonum = "no.txt";

if($_POST==$yes){
	function displayYes($yesnum) {
		$fpy = fopen($yesnum,rw);
		$ynum = fgets($fpy,9999);
		fclose($fpy);
		$fpy = fopen($yesnum,w);
		$ynum += 1;
		print "$ynum say yes";
		fputs($fpy, $ynum);
		fclose($fpy);
	}
} else {
	function displayNo($nonum) {
		$fpn = fopen($nonum,rw);
		$nnum = fgets($fpn,9999);
		fclose($fpn);
		$fpn = fopen($nonum,w);
		$nnum += 1;
		print "$nnum say no";
		fputs($fpn, $nnum);
		fclose($fpn);
	}
}

//Display the Current Hits
displayYes($yesnum);
displayNo($nonum);
?>

And here is the error:

Fatal error: Call to undefined function: displayyes() in /home/weeble/public_html/azzer/smell.php on line 32

[vass0922]

Granted I'm not a PHP developer, but I've never seen a language where you define a function within a conditional.
Usually you'll define the function off to the side, then you'll call the function within the conditional.

<?php
$yes = $_POST['yes']; $no = $_POST['no'];

$yesnum = "yes.txt";
$nonum = "no.txt";

if($_POST==$yes){
	displayYes($yesnum);
} else {
	displayNo($nonum);
}

//Display the Current Hits



	function displayYes($yesnum) {
		$fpy = fopen($yesnum,rw);
		$ynum = fgets($fpy,9999);
		fclose($fpy);
		$fpy = fopen($yesnum,w);
		$ynum += 1;
		print "$ynum say yes";
		fputs($fpy, $ynum);
		fclose($fpy);
	}

	function displayNo($nonum) {
		$fpn = fopen($nonum,rw);
		$nnum = fgets($fpn,9999);
		fclose($fpn);
		$fpn = fopen($nonum,w);
		$nnum += 1;
		print "$nnum say no";
		fputs($fpn, $nnum);
		fclose($fpn);
	}


?>

[Bill in SD, CA]

Might get some help here:

http://www.htmlforums.com/

Bill

[Weeble]

Cheers guys I got it sorted :P