ugly c++ problem

**oliver w** · January 23rd, 2006, 07:10 PM

I get a compilation error for the last line of the code

"in fuction 'main()' "
"in line 46 '}' expected"
even though i already have the '}' when i add another one it runs the program and
closes quickly (meaning there is an error)
any help would be apreciated!

Code:

 
#include <iostream>
#include <cstdlib>
#include <ctime>
int hitme() {
    int card;
    srand(time(NULL));
    card = rand()%11 + 0;  
    return(card);
    }
using namespace std;
int main() {
    int yc1, yc2, yc3, ytotal, ybank, ybet;
    int cc1, cc2, cc3, ctotal, cbank, cbet; 
    char hors, bet;
    ybank = 25;
    cbank = 25;
    cout<< "Welcome to blackjack!" << '\n' << '\n' << "Your cards are: ";
    yc1 = hitme();
    yc2 = hitme();
    cc1 = hitme();
    cc2 = hitme(); 
    ytotal = yc1 + yc2;
    ctotal = cc1 + cc2;
    cout<< yc1 << " and " << yc2 << " with a total of: " << ytotal;
    while (hors == 'h' || hors == 'H') {
        cout << '\n' << '\n'<< "'H' to hit, 'S' to stay ";
        cin >> hors;
        if (hors != 'h' || hors != 'H'){
        break;
        }
        yc3 = hitme();
        ytotal = ytotal + yc3;
        cout << '\n' << ytotal;
        if (ytotal > 21){
        cout << "BUST!!!";
        break;
        }
    cout<< "Do you want to bet on winning? 'Y' for yes" << '\n';
    cin >> bet;
    if (bet == 'Y' || bet == 'y') 
    cin >> ybet; 
    cout<< '\n' << "You have: " << ybank << " chips. How many would you like to bet? " << '\n';
    ybank = ybank - ybet;
    
    cin.get();
    return 0;
}

**jkrohn** · January 23rd, 2006, 07:18 PM

You are missing a close brace on your while loop.

As far as it exiting right away your while condition is false when the program starts.
Either convert it to a do while or give hors an intial value.

Not all that ugly

When you add another brace and it complies you have a logic error.

Jkrohn