Two Dimensional Array

[Krusho]

#include <stdio.h>

/* This function compares the strings */
int StrCmp(char *s, char *t, int length)
{
	/* Initializes i */
	int i;

	/* For loop that only returns value if s[i] is null */
	for(i = 0; i < length; i++)
		if(s[i] != t[1])
			return -1;

	return 0;
}

/* This function takes all the characters and makes them UPPERCASE */
int LowUpp(int ch)
{
	if ('a' <= ch && ch <= 'z')
	{
		return (ch + 'A' - 'a');
	}
	else
	{
		return ch;
	}
}

char c; /* Initializes c */

int main()
{
	
	int LowUpp(int ch);

	/* The following delcares the variables to be used in the program */
	char word[23];
	char userstring[1024];
	char Array[1024][100];
	int wordcount = 0;
	int charcount = 0;
	int wordnumb = 0;
	int i = 0;
	int j = 0;
	int row = 0;
	int column = 0;

	/* Next the Title and Enter your input are printed to the screen */
	printf("Word & Character Counter\n\n\n");
	printf("Enter your input ([CTRL+Z] To Quit): ");

	/* This if statement takes in the string from the user */
	if(fgets(userstring, 1024, stdin) == NULL)
		return 0;

	/* This prints the main parts of the table */
	printf("\n\nWord Count		");
	printf("Word			");
	printf("Character Count	\n");
	printf("---------------------------------------------------------------\n");

	/* This while loop continues as long as the userstring[i] is not null */
	while(userstring[i] != '\0')
	{ 
		/* If the userstring is equal to a space AND return AND tab */
		if((userstring[i] != ' ') && (userstring[i] != '\n') && (userstring[i] != '\t'))
		{ 
			/* Increments charcount */
			charcount++;

			/* Uses the LowUpp function on the input whichs turns in into uppercase */
			word[j++] = LowUpp(userstring[i]);
		}
		else
		{
			/* Increments wordnumb */
			wordnumb++;

			word[j] = '\0';

			/* Saves it to the array */
			Array[row][column] = word[i];

			/* If charcount is less than 8 */
			if(charcount < 8)
				/* Prints the input to the screen */
				printf("%d\t\t\t%s\t\t\t%d\n", wordnumb, word, charcount);
			else
				/* Prints the input to the screen */
				printf("%d\t\t\t%s\t%d\n", wordnumb, word, charcount);

			/* Sets charcount to 0 */
			charcount = 0;

			/* Increments wordcount  */
			wordcount++;

			/* Sets j equal to 0 */
			j = 0;
		}
		
		/* Increments i */
		i++;
	}
	
	/* Prints the end of the table to the screen */
	printf("---------------------------------------------------------------\n");
	printf("Total Words:  %d\n\n", wordcount);
	
	/* Returns 0 */
	return 0;
}

How can I put the input into a two dimensional array? And make it only output each occurence of the same word only once.

[strangerstill]

1. Iterate over two variables [i][j]
2. Hmm... some sort of associative array would seem to be indicated. As it's an unsorted usage, some type of hash table char * => int say could be the best (most efficient) way of doing it, however just a straight sorted array char *[] and int[] would be fairly easy to implement - use binary search to find the key index or insertion point, then ++int[i] or extend the arrays and insert the key-value pair (key being char *keyword, value being count := 1 at insertion) Alternatively a struct { char *; int } [] array might work quite well.

[Krusho]

Could you show me? I know the idea of what needs done I just can't picture exactly how to do it.