January 10th, 2003, 09:48 AM
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#1 (permalink)
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| Ultimate Member
Join Date: Oct 2001 Location: Savannah, GA
Posts: 1,752
| Code: menu.subMenus[1].addItem("FoldOutMenu","window.open('index.html')"); Working on getting a menu to function properly for a website. However, each link of the code opens in a new window!
Here's the format:
menu.subMenus[n].addItem([Menu Type],[Action])
Well, the action says window.open(' -link- ') --- How do I change this to open the link in the same window? |
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