use same function twice?

[Nathan323]

Howdy all

I am constructing a situation wherein mouseover of link image instigates appearance of a descriptive text image elsewhere.
<!------------------------------------------------------------------>
<SCRIPT LANGUAGE="JAVASCRIPT">
function image_over(image_name)
{
image_name.src = "Images/Desc - website.jpg"
}

function image_out(image_name)
{
image_name.src = "Images/BG-Fade3.jpg"
}
</SCRIPT>

<img name="NoText" src="Images/BG-Fade3.jpg">

<A ONMOUSEOVER="image_over(NoText)" onmouseout="image_out(NoText)"><IMG SRC="Images/website link.gif" BORDER=0></A>
<!------------------------------------------------------------------>
This code works fine with one link, but when mouseover occurs on the graphics link (in this example) I need the image "Desc - graphics.jpg" rather than "Desc - website.jpg" to appear (in the same spot).

<A ONMOUSEOVER="image_over(NoText)" onmouseout="image_out(NoText)"><IMG SRC="Images/graphics link.gif" BORDER=0></A>

Is there a way to dfferentiate between multiple instances of the same function?, ie. when the second link is hovered the "Desc - website.jpg" image is shown again, so can I write a second set of functions with some sort of unique identification specifically for each link?

This will be a big help.

Cheers - Nathan

[blandboringplain]

Ok, I tried your code. I found out that if you take your first set, and name them "image_over1" and "image_out1", that it worked just fine (make sure to call on them with the 1's in your code later). You can then make the next set, obviously, "image_over2" and "image_out2". Same thing applies with calling on it later. It worked fine for me this way.

[strangerstill]

Make it a function with 2 arguments.

[Nathan323]

Thanks for your help blandboringplain, that fixed it

Nathan

[blandboringplain]

No problem, glad I could do something.