extremely interestingQuestion about Array

[Ahsan Ullah Burk]

Hi Every oNe!!!

i have got a strange question its about the Pointers.
well before asking u the question can u suggest what should be the output of the following cod !!! Interesting isnt it...........
it out puts what i want i.e. the value of the varaible and the address of the variable but why why is it doing so when i am assinging its value to a pointer and that is never assinged to a variable ( a ) which is used to display its value . what i think of this program is that it will print the Garbage Value of the variable a and the memory address of the Pointer P;
Ur Help Needed !!!!!!

??????????????? ????????????? ????????


#include <stdlib.h>
#include <iostream.h>
#include <conio.h>

void main(void)
{
int *p;
int *c;
int a;

p=&a;
cout<<"Enter a Number\t";
cin>>*p;
cout<<"Value of the vairable = "<<a<<endl;
cout<<"Memory Address of the Variable = "<<p<<endl;
cout<<endl;

system("PAUSE");
}
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[pkanaby]

I don't quite understand your question. The pointer "p" is set to the address of "a", then you input "a" by dereferencing the pointer with the *. Then you simply print the value of "a" and then the address of "a". I'm not sure, but I think you may have looked over the part where you dereference "p" to use it as "a" for the input statement. If not, then I have misinterpreted what you were asking. Worth a shot.

-Phil (pkanaby@comcast.net)